How to sort an array of ints?

Question:
How do I do the following:

A user will input 3 different numbers and the program should return a 3-digit number in ascending order of the digits.

For example, if the user inputs 6, 1, 5 the returned integer should be 156.

Answer:
Put the three numbers in a array. Use the method Arrays.sort() to sort them. Then a little math to get to the final number.

Code:
import java.util.*;
 
public class SortNumbers {
 
   public static void main(String[] args) {
 
      Scanner sc = new Scanner(System.in);
 
      int[] input = new int[3];
 
      System.out.print("Enter Number: ");
      input[0] = sc.nextInt();
 
      System.out.print("Enter Number: ");
      input[1] = sc.nextInt();
 
      System.out.print("Enter Number: ");
      input[2] = sc.nextInt();
 
      System.out.println("Before: " + Arrays.toString(input));
      Arrays.sort(input);
      System.out.println("After: " + Arrays.toString(input));
 
      int number = input[0]*100;
      number = number + (input[1]*10);
      number = number + input[2];
 
      System.out.println("Number: " + number);
   }
}

Output:
$ java SortNumbers 
Enter Number: 6
Enter Number: 1
Enter Number: 5
Before: [6, 1, 5]
After: [1, 5, 6]
Number: 156
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